If log10 100 = 2, log10 101 = 2.004, log10 102 = 2.0086, log10: 103 = 2.0128 then ∫ limits100103 log10 xdx by Trapezoidal rule is

Question

If log10 100 = 2, log10 101 = 2.004, log10 102 = 2.0086, log10: 103 = 2.0128 then ∫ limits100103 log10 xdx by Trapezoidal rule is (A) 6.019 (B) 6.0019 (C) 6.1093 (D) 6.11993

Tardigrade Admin · Accepted Answer

∫ limits100103 f(x) dx ≅ (h/2) [ (y0 + y3) +2 ( y1+ y2 ) ] , h =1 .

Q. If $lo g_{10} 100 = 2, lo g_{10} 101 = 2.004$ , $lo g_{10} 102 = 2.0086, lo g_{10} 103 = 2.0128$ then $100 \int 103 lo g_{10} x d x$ by Trapezoidal rule is

6.019

6.0019

6.1093

6.11993

$100 \int 103 f (x) d x ≅ \frac{h}{2} [(y_{0} + y_{3}) + 2 (y_{1} + y_{2})], h = 1$ .

Q. If log10​100=2,log10​101=2.004, log10​102=2.0086,log10​103=2.0128 then 100∫103​log10​xdx by Trapezoidal rule is