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  4. If log10 100 = 2, log10 101 = 2.004, log10 102 = 2.0086, log10: 103 = 2.0128 then ∫ limits100103 log10 xdx by Trapezoidal rule is

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Q. If $\log_{10} 100 = 2,\log_{10} 101 = 2.004$, $\log_{10} 102 = 2.0086, \log_{10}\: 103 = 2.0128$ then $\int\limits_{100}^{103} \log_{10} \, xdx$ by Trapezoidal rule is

Application of Integrals

Solution:

$\int\limits_{100}^{103} f(x) \, dx \cong \frac{h}{2} [ (y_0 + y_3) +2 ( y_1+ y_2 ) ] , h =1 $ .