If limiting molar conductances of CH 3 COONa, HCl and NaCl are 91.0,426.2 and 126.5 S cm 2 mol -1, respectively at 25° C. The limiting molar conductance of CH 3 COOH, is S cm 2 mol -1.

Question

If limiting molar conductances of CH 3 COONa, HCl and NaCl are 91.0,426.2 and 126.5 S cm 2 mol -1, respectively at 25° C. The limiting molar conductance of CH 3 COOH, is S cm 2 mol -1. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Lambdam( CH 3 COOH )0= Lambda m ( CH 3 COONa )0+ Lambda m ( HCl )0- Lambda m ( NaCl )0 =91.0+426.2-126: 5 =390.7 S cm 2 mol -1

Q. If limiting molar conductances of $C H_{3} COON a$ , $H Cl$ and $N a Cl$ are $91.0, 426.2$ and $126.5 S c m^{2}$ $m o l^{- 1}$ , respectively at $2 5^{\circ} C$ . The limiting molar conductance of $C H_{3} COO H$ , is______ $S c m^{2} m o l^{- 1}$ .

$Λ_{m (C H_{3} COO H)}^{0} = Λ_{m (C H_{3} COON a)}^{0} + Λ_{m (H Cl)}^{0} - Λ_{m (N a Cl)}^{0}$
$= 91.0 + 426.2 - 126 : 5$
$= 390.7 S c m^{2} m o l^{- 1}$

Q. If limiting molar conductances of CH3​COONa, HCl and NaCl are 91.0,426.2 and 126.5Scm2 mol−1, respectively at 25∘C. The limiting molar conductance of CH3​COOH, is______ Scm2mol−1.

Λm(CH3​COOH)0​=Λm(CH3​COONa)0​+Λm(HCl)0​−Λm(NaCl)0​ =91.0+426.2−126:5 =390.7Scm2mol−1

Q. If limiting molar conductances of $C H_{3} COON a$ , $H Cl$ and $N a Cl$ are $91.0, 426.2$ and $126.5 S c m^{2}$ $m o l^{- 1}$ , respectively at $2 5^{\circ} C$ . The limiting molar conductance of $C H_{3} COO H$ , is______ $S c m^{2} m o l^{- 1}$ .

$Λ_{m (C H_{3} COO H)}^{0} = Λ_{m (C H_{3} COON a)}^{0} + Λ_{m (H Cl)}^{0} - Λ_{m (N a Cl)}^{0}$
$= 91.0 + 426.2 - 126 : 5$
$= 390.7 S c m^{2} m o l^{- 1}$