1. Tardigrade
  2. Question
  3. Chemistry
  4. If limiting molar conductances of CH 3 COONa, HCl and NaCl are 91.0,426.2 and 126.5 S cm 2 mol -1, respectively at 25° C. The limiting molar conductance of CH 3 COOH, is S cm 2 mol -1.

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Q. If limiting molar conductances of $CH _{3} COONa$, $HCl$ and $NaCl$ are $91.0,426.2$ and $126.5\, S\, cm ^{2}$ $mol ^{-1}$, respectively at $25^{\circ} C$. The limiting molar conductance of $CH _{3} COOH$, is______ $S\, cm ^{2} mol ^{-1}$.

Electrochemistry

Solution:

$\Lambda_{m\left( CH _{3} COOH \right)}^{0}=\Lambda_{ m \left( CH _{3} COONa \right)}^{0}+\Lambda_{ m ( HCl )}^{0}-\Lambda_{ m ( NaCl )}^{0}$
$=91.0+426.2-126: 5$
$=390.7\, S\, cm ^{2} mol ^{-1}$