Question

If in triangle $ABC,A\equiv (1,10)$, circumcentre $\equiv \left(-\frac{1}{3},\frac{2}{3}\right)$ and orthocentre $\equiv \left(\frac{11}{3},\frac{4}{3}\right)$ then the coordinates of midpoint of side opposite to $A$ is

• A. $(1,-11/3)$
• B. $(1,5)$
• C. $(1,-3)$
• D. $(1,6)$

Answer 1

Answer: (A)

$O,G,C$ are collinear. Get $G$.