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  4. If in triangle ABC , A ≡(1,10), circumcentre ≡(-(1/3), (2/3)) and orthocentre ≡((11/3), (4/3)) then the coordinates of midpoint of side opposite to A is

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Q. If in triangle $ABC , A \equiv(1,10)$, circumcentre $\equiv\left(-\frac{1}{3}, \frac{2}{3}\right)$ and orthocentre $\equiv\left(\frac{11}{3}, \frac{4}{3}\right)$ then the coordinates of midpoint of side opposite to $A$ is

Straight Lines

Solution:

$O, G, C$ are collinear. Get $G$.