Question

If in the circuit shown, voltmeter reads 100 V then L is

• A. 0.1 H
• B. 0.2 H
• C. 0.02 H
• D. 0.01 H

Answer 1

Answer: (D)

This is feasible only at resonance.
$\therefore 500=\frac{1}{2\pi \sqrt{LC}}$ or $\frac{1}{2\pi \sqrt{L\times 10\times 10^{-6}}}=500$
On solving, we get $L=0.01H$