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Q. If in the circuit shown, voltmeter reads 100 V then L isPhysics Question Image

Alternating Current

Solution:

This is feasible only at resonance.
$ \therefore \quad 500 = \frac{1}{2\pi\sqrt{LC}}$ or $\frac{1}{2\pi\sqrt{L\times10\times10^{-6}}} = 500$
On solving, we get $L = 0.01 \,H$