If heat of dissociation of CHCl2COOH is 0.7 k c a l / m o l e , the, Δ H for the reaction CHCl2COOH+KOH arrow CHCl2COOH+H2O is

Question

If heat of dissociation of CHCl2COOH is 0.7 k c a l / m o l e , the, Δ H for the reaction CHCl2COOH+KOH arrow CHCl2COOH+H2O is (A) - 13 text kcal (B) + 13 text kcal (C) - 14.4 text kcal (D) - 13.7 text kcal

Tardigrade Admin · Accepted Answer

Enthalpy of neutralization of strong acid and strong base is - 13.7 textkcal/mol Δ H= -13.7+0.7 = - 13.0 textkcal

Q. If heat of dissociation of $C H C l_{2} COO H$ is $0.7 k c a l / m o l e$ , the, $Δ H$ for the reaction

$C H C l_{2} COO H + K O H \to C H C l_{2} COO H + H_{2} O$ is

$- 13 kcal$

$+ 13 kcal$

$- 14.4 kcal$

$- 13.7 kcal$

Enthalpy of neutralization of strong acid and strong base is $- 13.7 kcal/mol$

$Δ H = - 13.7 + 0.7$

$= - 13.0 kcal$

Q. If heat of dissociation of CHCl2​COOH is 0.7kcal/mole , the, ΔH for the reaction CHCl2​COOH+KOH→CHCl2​COOH+H2​O is

−13 kcal

+13 kcal

−14.4 kcal

−13.7 kcal