Question

If heat of dissociation of $CHCl_{2}COOH$ is $0.7 \, k c a l / m o l e$ , the, $\Delta H$ for the reaction

$CHCl_{2}COOH+KOH \rightarrow CHCl_{2}COOH+H_{2}O$ is

• A. $- 13 \text{ kcal}$
• B. $+ 13 \text{ kcal}$
• C. $- 14.4 \text{ kcal}$
• D. $- 13.7 \text{ kcal}$

Answer 1

Answer: (A)

Enthalpy of neutralization of strong acid and strong base is $- 13.7 \, \text{kcal/mol}$

$\Delta H= \, -13.7+0.7$

$= - 13.0 \, \text{kcal}$