Question

If $g\left(x\right)=\underset{0}{\overset{x}{\int }}$ cos 4t dt, then $g\left(x+\pi \right)$ equals

• A. $\frac{g\left(x\right)}{g\left(\pi \right)}$
• B. $g\left(x\right)+g\left(\pi \right)$
• C. $g\left(x\right)-g\left(\pi \right)$
• D. $g\left(x\right).g\left(\pi \right)$

Answer 1

Answer: (B), (C)

$g\left(x\right)=\underset{0}{\overset{x+\pi }{\int }}$ cos 4t dt, $=g\left(x\right)+\underset{0}{\overset{\pi }{\int }}$ cos 4t dt
$=g\left(x\right)+g\left(\pi \right)$
Here $g\left(\pi \right)=\underset{0}{\overset{\pi }{\int }}$cos 4t dt $=0$
so answers are $\left(2\right)$ or $\left(3\right)$