If for the reaction N 2+3 H 2 leftharpoons 2 NH 3, Δ H=-92.38 kJ / mol, then what happens if the temperature is increased?

Question

If for the reaction N 2+3 H 2 leftharpoons 2 NH 3, Δ H=-92.38 kJ / mol, then what happens if the temperature is increased? (A) Reaction proceed forward (B) Reaction proceed backward (C) No effect on the formation of product (D) None of these

Tardigrade Admin · Accepted Answer

Reaction proceed backward according to Le-chatelier's principle.

Q. If for the reaction N2​+3H2​⇌2NH3​,ΔH=−92.38kJ/mol, then what happens if the temperature is increased?

Reaction proceed forward

Reaction proceed backward

No effect on the formation of product

None of these

Reaction proceed backward according to Le-chatelier's principle.

Q. If for the reaction
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}, Δ H = - 92.38 k J / m o l$ , then what happens if the temperature is increased?