1. Tardigrade
  2. Question
  3. Chemistry
  4. If for the reaction N 2+3 H 2 leftharpoons 2 NH 3, Δ H=-92.38 kJ / mol, then what happens if the temperature is increased?

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Q. If for the reaction
$N _2+3 H _2 \rightleftharpoons 2 NH _3, \Delta H=-92.38 \,kJ / mol$, then what happens if the temperature is increased?

Equilibrium

Solution:

Reaction proceed backward according to Le-chatelier's principle.