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Question
Mathematics
If f(x)=|x-3 2 x2-18 3 x3-81 x-5 2 x2-50 4 x3-500 1 2 3| then f(1) f(3)+f(3) f(5)+f(5) f(1) is equal to
Q. If
f
(
x
)
=
∣
∣
x
−
3
x
−
5
1
2
x
2
−
18
2
x
2
−
50
2
3
x
3
−
81
4
x
3
−
500
3
∣
∣
then
f
(
1
)
f
(
3
)
+
f
(
3
)
f
(
5
)
+
f
(
5
)
f
(
1
)
is equal to
70
102
Determinants
Report Error
A
f
(
1
)
+
f
(
5
)
12%
B
f
(
3
)
+
f
(
5
)
24%
C
f
(
1
)
+
f
(
3
)
6%
D
f
(
1
)
+
f
(
3
)
+
f
(
5
)
57%
Solution:
Clearly
f
(
3
)
=
∣
∣
0
−
2
1
0
−
32
2
0
−
392
3
∣
∣
=
0
and
f
(
5
)
=
∣
∣
2
0
1
32
0
2
294
0
3
∣
∣
=
0
, where
f
(
1
)
=
0
∴
f
(
1
)
f
(
3
)
+
f
(
3
)
f
(
5
)
+
f
(
5
)
f
(
1
)
=
0
=
f
(
3
)
+
f
(
5
)