Question

If $f(x)=x^3-1,$ then find $\frac{[f(3)+f(2)]}{11}$

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (C)

Given, $f(x)=x^3-1$
$\therefore$ $f(3)={(3)}^3-1=27-1=26$
$f(2)={(2)}^3-1=8-1=7$
Now, $\frac{f(x)+f(2)}{11}=\frac{26+7}{11}=\frac{33}{11}=3$