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Q. If $ f(x)={{x}^{3}}-1, $ then find $\frac { [f(3)+f(2)]} {11} $

J & K CETJ & K CET 2014Relations and Functions

Solution:

Given, $ f(x)={{x}^{3}}-1 $
$ \therefore $ $ f(3)={{(3)}^{3}}-1=27-1=26 $
$ f(2)={{(2)}^{3}}-1=8-1=7 $
Now, $ \frac{f(x)+f(2)}{11}=\frac{26+7}{11}=\frac{33}{11}=3 $