If equivalent conductance of 1M benzoic acid is 12.8ohm - 1cm2eq- 1 and the equivalent conductance of benzoate ion and H+ ion at infinite dilution are 42 and 288.42ohm- 1cm2eq- 1 respectively then its degree of dissociation is :-

Question

If equivalent conductance of 1M benzoic acid is 12.8ohm - 1cm2eq- 1 and the equivalent conductance of benzoate ion and H+ ion at infinite dilution are 42 and 288.42ohm- 1cm2eq- 1 respectively then its degree of dissociation is :- (A) 39 % (B) 3.9 % (C) 0.35 % (D) 0.039 %

Tardigrade Admin · Accepted Answer

Degree of dissociation (.α .)=((λ )m/λ m∞ ) ∴ α =(12 . 8/42 + 288 . 42)× 100=3.9 %

Q. If equivalent conductance of $1 M$ benzoic acid is $12.8 o hm_^{- 1} c m^{2} e q^{- 1}$ and the equivalent conductance of benzoate ion and $H^{+}$ ion at infinite dilution are $42$ and $288.42 o h m^{- 1} c m^{2} e q^{- 1}$ respectively then its degree of dissociation is :-

$39%$

$3.9%$

$0.35%$

$0.039%$

Degree of dissociation $(α) = \frac{( λ ) _{m}}{λ _{m}^{\infty}}$
$∴ α = \frac{12.8}{42 + 288.42} \times 100 = 3.9%$

Q. If equivalent conductance of 1M benzoic acid is 12.8ohm_−1cm2eq−1 and the equivalent conductance of benzoate ion and H+ ion at infinite dilution are 42 and 288.42ohm−1cm2eq−1 respectively then its degree of dissociation is :-

39%

3.9%

0.35%

0.039%