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Question
Chemistry
If equal volumes of 1 M KMnO4 and 1 M K2Cr2O7 solutions are allowed to oxidise Fe(II) to Fe(III) in acidic medium, then Fe (II) oxidised will be
Q. If equal volumes of
1
M
K
M
n
O
4
and
1
M
K
2
C
r
2
O
7
solutions are allowed to oxidise
F
e
(
II
)
to
F
e
(
III
)
in acidic medium, then
F
e
(
II
)
oxidised will be
3013
247
Redox Reactions
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A
more by
K
M
n
O
4
22%
B
more by
K
2
C
r
2
O
7
72%
C
equal in both the cases
7%
D
can’t be determined
0%
Solution:
5
F
e
2
+
M
n
O
4
Θ
+
8
H
⊕
→
5
F
e
3
+
+
4
H
2
O
+
M
n
2
+
6
F
e
2
+
+
C
r
2
O
7
2
−
+
14
H
⊕
→
6
F
e
3
+
+
7
H
2
O
+
2
C
r
3
+
From these reactions, it can be seen that
F
e
(II) will be oxidised more by
K
2
C
r
2
O
7