1. Tardigrade
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  3. Chemistry
  4. If equal volumes of 1 M KMnO4 and 1 M K2Cr2O7 solutions are allowed to oxidise Fe(II) to Fe(III) in acidic medium, then Fe (II) oxidised will be

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Q. If equal volumes of $1 \, M \, KMnO_4$ and $1 \, M \, K_2Cr_2O_7$ solutions are allowed to oxidise $Fe(II)$ to $Fe(III)$ in acidic medium, then $Fe (II)$ oxidised will be

Redox Reactions

Solution:

$5 Fe ^{2+} MnO _{4}^{\Theta}+8 H ^{\oplus} \rightarrow 5 Fe ^{3+}+4 H _{2} O + Mn ^{2+}$
$6 Fe ^{2+}+ Cr _{2} O _{7}^{2-}+14 H ^{\oplus} \rightarrow 6 Fe ^{3+}+7 H _{2} O +2 Cr ^{3+}$
From these reactions, it can be seen that $Fe$ (II) will be oxidised more by $K _{2} Cr _{2} O _{7}$