If empirical formula of an organic compound is CH2O and its 6.02 × 1023 molecules weigh 60 g, then it can be

Question

If empirical formula of an organic compound is CH2O and its 6.02 × 1023 molecules weigh 60 g, then it can be (A)  CH3OH (B) C2H5OH (C) HCOOH (D) HCOOCH3

Tardigrade Admin · Accepted Answer

1 mol = 60 g E.F. mass = 12 + 2 × 1 + 16 = 30 g Molecular mass = 60 g = 2 × 30 = 2 × (E.F. mass) Molecular formula = 2 + E.F. = 2(CH2O) = C2H2O2 i.e., HCOOCH3

Q. If empirical formula of an organic compound is $C H_{2} O$ and its $6.02 \times 1 0^{23}$ molecules weigh 60 g, then it can be

$C H_{3} O H$

$C_{2} H_{5} O H$

HCOOH

$H COOC H_{3}$

1 mol = 60 g
E.F. mass = 12 + 2 $\times$ 1 + 16 = 30 g
Molecular mass = 60 g = 2 $\times$ 30
= 2 $\times$ (E.F. mass)
Molecular formula = 2 + E.F. = $2 (C H_{2} O)$
= $C_{2} H_{2} O_{2}$ i.e., $H COOC H_{3}$

Q. If empirical formula of an organic compound is CH2​O and its 6.02×1023 molecules weigh 60 g, then it can be

CH3​OH

C2​H5​OH