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Q. If empirical formula of an organic compound is $CH_2O$ and its $6.02 \times 10^{23}$ molecules weigh 60 g, then it can be

Organic Chemistry – Some Basic Principles and Techniques

Solution:

1 mol = 60 g
E.F. mass = 12 + 2 $\times$ 1 + 16 = 30 g
Molecular mass = 60 g = 2 $\times$ 30
= 2 $\times$ (E.F. mass)
Molecular formula = 2 + E.F. = $2(CH_2O)$
= $C_2H_2O_2$ i.e., $HCOOCH_3$