If electronegativity of A is 2.0 and that of B is 3.0 , what is the covalent character percentage of the bond A-B ?

Question

If electronegativity of A is 2.0 and that of B is 3.0 , what is the covalent character percentage of the bond A-B ? (A) 19.5 % (B) 80.5 % (C) 46 % (D) 54 %

Tardigrade Admin · Accepted Answer

% Ionic character =16( chiA- chiB)+3.5( chiA- chiB)2 =16(3-2)+3.5(3-2)2 =16+3.5=19.5 % covalent character Covalent character =100-19.5=80.5 %

Q. If electronegativity of $A$ is $2.0$ and that of $B$ is $3.0$ , what is the covalent character percentage of the bond $A - B ?$

$19.5%$

$80.5%$

$46%$

$54%$

$%$ Ionic character $= 16 (χ_{A} - χ_{B}) + 3.5 (χ_{A} - χ_{B})^{2}$

$= 16 (3 - 2) + 3.5 (3 - 2)^{2}$

$= 16 + 3.5 = 19.5%$ covalent character

Covalent character $= 100 - 19.5 = 80.5%$

Q. If electronegativity of A is 2.0 and that of B is 3.0 , what is the covalent character percentage of the bond A−B?

19.5%

80.5%

46%

54%