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Q. If electronegativity of $A$ is $2.0$ and that of $B$ is $3.0$ , what is the covalent character percentage of the bond $A-B ?$

Classification of Elements and Periodicity in Properties

Solution:

$ \%$ Ionic character $=16\left(\chi_{A}-\chi_{B}\right)+3.5\left(\chi_{A}-\chi_{B}\right)^{2}$

$\quad=16(3-2)+3.5(3-2)^{2}$

$\quad=16+3.5=19.5 \%$ covalent character

Covalent character $=100-19.5=80.5 \%$