If effective length of a simple pendulum is equal to radius of earth (R), time period will be

Question

If effective length of a simple pendulum is equal to radius of earth (R), time period will be (A) T=π √(R/g) (B) T=2 π √(2 R/g) (C) T=2 π √(R/g) (D) T=2 π √(R/2 g)

Tardigrade Admin · Accepted Answer

T=2 π √(1/g((1)R+(1)l) ∵ l=R ∴ T=2 π √(R/2 g)

Q. If effective length of a simple pendulum is equal to radius of earth $(R)$ , time period will be

$T = π \frac{R}{g}$

$T = 2 π \frac{2 R}{g}$

$T = 2 π \frac{R}{g}$

$T = 2 π \frac{R}{2 g}$

$T = 2 π \frac{1}{g ( \frac{1}{R} + \frac{1}{l} )}$
$∵ l = R$
$∴ T = 2 π \frac{R}{2 g}$

Q. If effective length of a simple pendulum is equal to radius of earth (R), time period will be

T=πgR​​

T=2πg2R​​

T=2πgR​​

T=2π2gR​​