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  4. If effective length of a simple pendulum is equal to radius of earth (R), time period will be

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Q. If effective length of a simple pendulum is equal to radius of earth $(R)$, time period will be

Oscillations

Solution:

$T=2 \pi \sqrt{\frac{1}{g\left(\frac{1}{R}+\frac{1}{l}\right)}}$
$\because l=R $
$\therefore T=2 \pi \sqrt{\frac{R}{2 g}}$