Question

If earth is considered as metallic sphere, then its capacity will be

• A. $700\mu F$
• B. $6.4\times 10^{5}F$
• C. $710\mu F$
• D. $700F$

Answer 1

Answer: (C)

As $C=4\pi {\epsilon }_{0}R$
Here, $R=6.4\times 10^{6}m$, $4\pi {\epsilon }_0=\frac{1}{9\times 10^9}N{C}^{-2}{m}^2$
$\therefore C=\frac{6.4\times 10^6}{9\times 10^9}$
$=710\times 10^{-6}F=710\mu F$