If E and B are the magnitudes of electric and magnetic fields respectively in some region of space, then the possibilities for which a charged particle may move in that space with a uniform velocity of magnitude v are

Question

If E and B are the magnitudes of electric and magnetic fields respectively in some region of space, then the possibilities for which a charged particle may move in that space with a uniform velocity of magnitude v are (A) E = vB (B) E ≠ 0, B = 0 (C) E = 0, B ≠ 0 (D) E ≠ 0, B ≠ 0

Tardigrade Admin · Accepted Answer

The charged particle will move with uniform velocity in that space if E=0 and B ≠ 0, since a moving charge in a magnetic field experience a force. Also if E ≠ 0, B ≠ 0, the charged particle will move with uniform velocity in that space. If E=v B, then particle again moves with uniform velocity.

Q. If $E$ and $B$ are the magnitudes of electric and magnetic fields respectively in some region of space, then the possibilities for which a charged particle may move in that space with a uniform velocity of magnitude $v$ are

$E = v B$

$E \neq = 0, B = 0$

$E = 0, B \neq = 0$

$E \neq = 0, B \neq = 0$

Q. If E and B are the magnitudes of electric and magnetic fields respectively in some region of space, then the possibilities for which a charged particle may move in that space with a uniform velocity of magnitude v are

E=vB

E=0,B=0

E=0,B=0

E=0,B=0

The charged particle will move with uniform velocity in that space if E=0 and B=0, since a moving charge in a magnetic field experience a force. Also if E=0,B=0, the charged particle will move with uniform velocity in that space. If E=vB, then particle again moves with uniform velocity.

Q. If $E$ and $B$ are the magnitudes of electric and magnetic fields respectively in some region of space, then the possibilities for which a charged particle may move in that space with a uniform velocity of magnitude $v$ are

$E = v B$

$E \neq = 0, B = 0$

$E = 0, B \neq = 0$

$E \neq = 0, B \neq = 0$