Q. If distance between two non-intersecting planes $P_{1}$ and $P_{2}$ is 3 units, where $P_{1}$ is $2 x - 3 y + 6 z + 5 = 0$ and $P_{2}$ is $4 x + b y + cz + d = 0$ and point $A (- 3, 0, - 1)$ is lying between the planes $P_{1}$ and $P_{2}$ then the value of $(b + c + d)$ , is equal to

67 108 Vector Algebra Report Error

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