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  4. If distance between two non-intersecting planes P1 and P2 is 3 units, where P1 is 2 x-3 y+6 z+5=0 and P2 is 4 x+b y+c z+d=0 and point A(-3,0,-1) is lying between the planes P1 and P2 then the value of (b+c+d), is equal to

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Q. If distance between two non-intersecting planes $P_1$ and $P_2$ is 3 units, where $P_1$ is $2 x-3 y+6 z+5=0$ and $P_2$ is $4 x+b y+c z+d=0$ and point $A(-3,0,-1)$ is lying between the planes $P_1$ and $P_2$ then the value of $(b+c+d)$, is equal to

Vector Algebra

Solution:

Correct answer is (c) 58