Question

If boiling point of water is $95{}^{\circ }F,$ what will be reduction at celsius scale?

• A. $7{}^{\circ }C$
• B. $65{}^{\circ }C$
• C. $63{}^{\circ }C$
• D. $35{}^{\circ }C$

Answer 1

Answer: (D)

The relation between Celsius scale and Fahrenheit scale is as derived below:

$100$ parts of Celsius scale $=180$ parts of Fahrenheit scale
$\therefore$ 1 part of Celsius scale
$=\frac{9}{5}$ parts of Fahrenheit scale Hence, $T_F=32+\frac{9}{5}{T}_C$ Or $T_C=\frac{5}{9}(T_F-32)$
Given, $T_F={95}^{o}F$
$\therefore$ $T_C=\frac{5}{9}(95-32)$
$={35}^{o}C$