Question

If boiling point of water is $ 95{}^\circ F, $ what will be reduction at celsius scale?

• A. $ 7{}^\circ C $
• B. $ 65{}^\circ C $
• C. $ 63{}^\circ \text{ }C $
• D. $ 35{}^\circ C $

Answer 1

Answer: (D)

The relation between Celsius scale and Fahrenheit scale is as derived below:

$100$ parts of Celsius scale $= 180$ parts of Fahrenheit scale
$ \therefore $ 1 part of Celsius scale
$=\frac{9}{5} $ parts of Fahrenheit scale Hence, $ {{T}_{F}}=32+\frac{9}{5}{{T}_{C}} $ Or $ {{T}_{C}}=\frac{5}{9}({{T}_{F}}-32) $
Given, $ {{T}_{F}}={{95}^{o}}F $
$ \therefore $ $ {{T}_{C}}=\frac{5}{9}(95-32) $
$={{35}^{o}}C $