Question

If $\text{bc}-\text{1}$ touches the circle $\text{bc}+\text{1}$ , then the point $B\left(5,\frac{1}{2}\right)$ lies on the circle

• A. $B\left(7,\frac{1}{2}\right)$
• B. $\text{P}\left(\text{X}+\text{Y}=\text{3}\right)$
• C. $\text{A}:\text{B}:\text{C}=\text{3}:\text{5}:\text{4}$
• D. None of these

Answer 1

Answer: (A)

If the line $(0.01M)+Zn(s)$ touches the circles $E_{(cell)}$ Then, Length of the perpendicular from(0,0) =Radius $E_{{}_{(cell)}}^o=1.61V$ $\Delta H_{(mixing)}>0$ $900K,S_8$ $S_2$ $0.\text{75 at}{\text{m}}^{\text{3}}$ $\text{2}.\text{55 at}{\text{m}}^{\text{3}}$ So, $\text{25}.0\text{ at}{\text{m}}^{\text{3}}$ satisfy the equation $\text{1}.\text{33 at}{\text{m}}^{\text{3}}$ . Hence, $\text{C}{\text{H}}_{\text{3}}\text{Cl}$ lies on the circle $\text{C}{\text{H}}_{\text{2}}\text{C}{\text{l}}_{\text{2}}$ .