If average binding energy per nucleon of X and Y is 8.5MeV whereas that of 92236U is 7.6MeV . Then the total energy liberated in the following reaction is 92236U overset arrow 117X+ 117Y+n+n

Question

If average binding energy per nucleon of X and Y is 8.5MeV whereas that of 92236U is 7.6MeV . Then the total energy liberated in the following reaction is 92236U overset arrow 117X+ 117Y+n+n (A) 200keV (B) 2MeV (C) 200MeV (D) 2000MeV

Tardigrade Admin · Accepted Answer

Average binding energy per nucleon of XandY=8.5MeV Binding energy per nucleon of U=7.6MeV where binding energy arrow B.E. So total energy liberated =(B . E . o f X + B . E . o f Y - B . E . o f U)=(117 × 8 . 5 + 117 × 8 . 5 - 236 × 7 . 6)=195.4≈200MeV

Q. If average binding energy per nucleon of $X$ and $Y$ is $8.5 M e V$ whereas that of $_92^{236} U$ is $7.6 M e V$ . Then the total energy liberated in the following reaction is
$_92^{236} U \to_^{117} X +_^{117} Y + n + n$

$200 k e V$

$2 M e V$

$200 M e V$

$2000 M e V$

Average binding energy per nucleon of $X an d Y = 8.5 M e V$
Binding energy per nucleon of $U = 7.6 M e V$
where binding energy $\to B . E .$
So total energy liberated $= (B . E . o f X + B . E . o f Y - B . E . o f U) = (117 \times 8.5 + 117 \times 8.5 - 236 \times 7.6) = 195.4 \approx 200 M e V$

Q. If average binding energy per nucleon of X and Y is 8.5MeV whereas that of _92236U is 7.6MeV . Then the total energy liberated in the following reaction is _92236U→_117X+_117Y+n+n

200keV

2MeV

200MeV

2000MeV