Question

If average binding energy per nucleon of $X$ and $Y$ is $8.5MeV$ whereas that of $\_{92}^{236}U$ is $7.6MeV$ . Then the total energy liberated in the following reaction is
$\_{92}^{236}U\overset{}{ \rightarrow }\_{}^{117}X+\_{}^{117}Y+n+n$

• A. $200keV$
• B. $2MeV$
• C. $200MeV$
• D. $2000MeV$

Answer 1

Answer: (C)

Average binding energy per nucleon of $XandY=8.5MeV$
Binding energy per nucleon of $U=7.6MeV$
where binding energy $ \rightarrow B.E.$
So total energy liberated $=\left(B . E . o f X + B . E . o f Y - B . E . o f U\right)=\left(117 \times 8 . 5 + 117 \times 8 . 5 - 236 \times 7 . 6\right)=195.4\approx200MeV$