If at least one child in a family with 3 children is a boy then the probability that exactly 2 of the children are boys, is

Question

If at least one child in a family with 3 children is a boy then the probability that exactly 2 of the children are boys, is (A) 3/7 (B) 4/7 (C) 1/3 (D) 3/8

Tardigrade Admin · Accepted Answer

n ( S )= B G G (3); B B G (3); B B B (1); hence n ( S )=7 n ( A )= BBG (3) ⇒ p =(3/7)

Q. If at least one child in a family with 3 children is a boy then the probability that exactly 2 of the children are boys, is

3/7

4/7

1/3

3/8

$n (S) =$ B G G (3); B B G (3); B B B (1); hence $n (S) = 7$
$n (A) = BBG (3) \Rightarrow p = \frac{3}{7}$

Q. If at least one child in a family with 3 children is a boy then the probability that exactly 2 of the children are boys, is

3/7

4/7

1/3

3/8

n(S)= B G G (3); B B G (3); B B B (1); hence n(S)=7 n(A)=BBG(3)⇒p=73​

$n (S) =$ B G G (3); B B G (3); B B B (1); hence $n (S) = 7$
$n (A) = BBG (3) \Rightarrow p = \frac{3}{7}$