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Mathematics
If at least one child in a family with 3 children is a boy then the probability that exactly 2 of the children are boys, is
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Q. If at least one child in a family with 3 children is a boy then the probability that exactly 2 of the children are boys, is
Probability - Part 2
A
3/7
B
4/7
C
1/3
D
3/8
Solution:
$n ( S )=$ B G G (3); B B G (3); B B B (1); hence $n ( S )=7$
$n ( A )= BBG (3) \Rightarrow p =\frac{3}{7}$