If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been

Question

If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been (A) 2 (B) 6 (C) 8 (D) 10

Tardigrade Admin · Accepted Answer

l=0, 1,2...n instead of 0,1,2...(n-1) beginalign For n=1 Orbitals electrons l=0, m=0 one 2 l=1, m=-1, 0 1 three 6 endalign Total no. of electrons =2+6=8

Q. If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been

2

6

8

10

$l = 0, 1, 2... n$ instead of $0, 1, 2... (n - 1)$ $F or n = 1 O r bi t a l s e l ec t ro n s l = 0, m = 0 o n e 2 l = 1, m = - 1, 01 t h ree 6$ Total no. of electrons $= 2 + 6 = 8$

Q. If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been

2

6

8

10

l=0,1,2...n instead of 0,1,2...(n−1) ​Forn=1Orbitalselectronsl=0,m=0one2l=1,m=−1,01three6​ Total no. of electrons =2+6=8

$l = 0, 1, 2... n$ instead of $0, 1, 2... (n - 1)$ $F or n = 1 O r bi t a l s e l ec t ro n s l = 0, m = 0 o n e 2 l = 1, m = - 1, 01 t h ree 6$ Total no. of electrons $= 2 + 6 = 8$