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  4. If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been

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Q. If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been

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Solution:

$ l=0,\,1,2...n $ instead of $ 0,1,2...(n-1) $ $ \begin{align} & For\,n=1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Orbitals\,\,\,\,electrons \\ & l=0,\,m=0\,\,\,\,\,\,\,\,\,\,\,\,\,one\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2 \\ & l=1,\,m=-1,\,0\,\,\,\,\,\,1\,three\,\,\,\,\,\,\,\,\,\,\,\,\,6\,\,\,\,\, \\ \end{align} $ Total no. of electrons $ =2+6=8 $