Question

If angular momentum quantum number can take value of n also (in addition to other possible values) then total number of electrons in first orbit would have been

• A. 2
• B. 6
• C. 8
• D. 10

Answer 1

Answer: (C)

$l=0,\,1,2...n$ instead of $0,1,2...(n-1)$ $\begin{align} & For\,n=1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Orbitals\,\,\,\,electrons \\ & l=0,\,m=0\,\,\,\,\,\,\,\,\,\,\,\,\,one\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2 \\ & l=1,\,m=-1,\,0\,\,\,\,\,\,1\,three\,\,\,\,\,\,\,\,\,\,\,\,\,6\,\,\,\,\, \\ \end{align}$ Total no. of electrons $=2+6=8$