If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( c is speed of light)

Question

If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( c is speed of light) (A) (3 R c/29) (B) (5 R c/36) (C) (7 R c/36) (D) (8 R c/31)

Tardigrade Admin · Accepted Answer

(1/λ)=R((1/22)-(1/32)) f=Re c((1/4)-(1/9)) f=(R c 5/36)=(5 R c/36)

Q. If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( $c$ is speed of light)

$\frac{3 R c}{29}$

$\frac{5 R c}{36}$

$\frac{7 R c}{36}$

$\frac{8 R c}{31}$

$\frac{1}{λ} = R (\frac{1}{2 ^{2}} - \frac{1}{3 ^{2}})$
$f = R_{e} c (\frac{1}{4} - \frac{1}{9})$
$f = \frac{R c 5}{36} = \frac{5 R c}{36}$

Q. If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( c is speed of light)

293Rc​

365Rc​

367Rc​

318Rc​