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  4. If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( c is speed of light)

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Q. If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( $c$ is speed of light)

Atoms

Solution:

$\frac{1}{\lambda}=R\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)$
$f=R_{e} c\left(\frac{1}{4}-\frac{1}{9}\right)$
$f=\frac{R c 5}{36}=\frac{5 R c}{36}$