Question

If an electron in H atom has an energy of-78.4 kcal/mol. The orbit in which the electron is present is:-

• A. $1^{st}$
• B. $2^{nd}$
• C. $3^{rd}$
• D. $4^{th}$

Answer 1

Answer: (B)

$E^n=\frac{-313.6}{n^2}kcal/mol$

$\Rightarrow -78.4=\frac{-313.6}{n^2}$

$\therefore n=2$