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Q. If an electron in H atom has an energy of-78.4 kcal/mol. The orbit in which the electron is present is:-

Structure of Atom

Solution:

$E ^{ n }=\frac{-313.6}{ n ^{2}} kcal / mol$

$\Rightarrow -78.4=\frac{-313.6}{ n ^{2}}$

$\therefore n =2$