If an electron in a hydrogen atom is in its 2nd excited state, orbiting the nucleus in a stationary orbit of radius 4.65 overset° A , then its de-Broglie wavelength is

Question

If an electron in a hydrogen atom is in its 2nd excited state, orbiting the nucleus in a stationary orbit of radius 4.65 overset° A , then its de-Broglie wavelength is (A) 12.9 overset° A (B) 3.5 overset° A (C) 9.7 overset° A (D) 6.6 overset° A

Tardigrade Admin · Accepted Answer

2π r=nλ ⇒ 2π =3λ λ =9.7A

Q. If an electron in a hydrogen atom is in its $2^{n d}$ excited state, orbiting the nucleus in a stationary orbit of radius $4.65 A^{\circ}$ , then its de-Broglie wavelength is

$12.9 A^{\circ}$

$3.5 A^{\circ}$

$9.7 A^{\circ}$

$6.6 A^{\circ}$

$2 π r = nλ$
$\Rightarrow 2 π = 3 λ$
$λ = 9.7 A$

Q. If an electron in a hydrogen atom is in its 2nd excited state, orbiting the nucleus in a stationary orbit of radius 4.65A∘ , then its de-Broglie wavelength is

12.9A∘

3.5A∘

9.7A∘

6.6A∘