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Q. If an electron in a hydrogen atom is in its $2^{nd}$ excited state, orbiting the nucleus in a stationary orbit of radius $4.65 \, \overset{^\circ }{A}$ , then its de-Broglie wavelength is

NTA AbhyasNTA Abhyas 2020Atoms

Solution:

$2\pi r=n\lambda $
$\Rightarrow 2\pi =3\lambda $
$\lambda =9.7A$