If α1

Question

If α1< α2< α3< α4< α5< α6, then the equation (x-α1)(x-α3)(x-α5)+3(x-α2)(x-α4)(x-α6)=0 has - (A) three real roots (B) no real root in (-∞, α1) (C) one real root in (α1, α2) (D) no real root in (α5, α6)

Tardigrade Admin · Accepted Answer

Correct answer is (a) three real rootsCorrect answer is (b) no real root in (-∞, α1)Correct answer is (c) one real root in (α1, α2)

Q. If $α_{1} < α_{2} < α_{3} < α_{4} < α_{5} < α_{6}$ , then the equation $(x - α_{1}) (x - α_{3}) (x - α_{5}) + 3 (x - α_{2}) (x - α_{4}) (x - α_{6}) = 0$ has -

three real roots

no real root in $(- \infty, α_{1})$

one real root in $(α_{1}, α_{2})$

no real root in $(α_{5}, α_{6})$

Correct answer is (a) three real rootsCorrect answer is (b) no real root in $(- \infty, α_{1})$ Correct answer is (c) one real root in $(α_{1}, α_{2})$

Q. If α1​<α2​<α3​<α4​<α5​<α6​, then the equation (x−α1​)(x−α3​)(x−α5​)+3(x−α2​)(x−α4​)(x−α6​)=0 has -

three real roots

no real root in (−∞,α1​)

one real root in (α1​,α2​)

no real root in (α5​,α6​)

Correct answer is (a) three real rootsCorrect answer is (b) no real root in (−∞,α1​) Correct answer is (c) one real root in (α1​,α2​)

Q. If $α_{1} < α_{2} < α_{3} < α_{4} < α_{5} < α_{6}$ , then the equation $(x - α_{1}) (x - α_{3}) (x - α_{5}) + 3 (x - α_{2}) (x - α_{4}) (x - α_{6}) = 0$ has -

no real root in $(- \infty, α_{1})$

one real root in $(α_{1}, α_{2})$

no real root in $(α_{5}, α_{6})$

Correct answer is (a) three real rootsCorrect answer is (b) no real root in $(- \infty, α_{1})$ Correct answer is (c) one real root in $(α_{1}, α_{2})$