Question

If a person throw 3 dice, the probability of getting sum of digit exactly 15 is :

• A. $\frac{1}{108}$
• B. $\frac{2}{109}$
• C. $\frac{5}{108}$
• D. $\frac{3}{108}$

Answer 1

Answer: (C)

Sum 15 = (3, 6, 6), (4, 5, 6) (5, 5, 5) (3 cases) (6 cases) (1 case)
Favourable cases = 10
Probability = $\frac{10}{6^3}=\frac{5}{108}$