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  4. If a person throw 3 dice, the probability of getting sum of digit exactly 15 is :

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Q. If a person throw 3 dice, the probability of getting sum of digit exactly 15 is :

Probability

Solution:

Sum 15 = (3, 6, 6), (4, 5, 6) (5, 5, 5) (3 cases) (6 cases) (1 case)
Favourable cases = 10
Probability = $\frac{10}{6^3} = \frac{5}{108}$