If a machine performs 4000 J of output work and 1000 J is energy loss due to friction then, find efficiency of machine

Question

If a machine performs 4000 J of output work and 1000 J is energy loss due to friction then, find efficiency of machine (A) 20% (B) 25% (C) 80% (D) 60%

Tardigrade Admin · Accepted Answer

Efficiency = (output work/heat taken) =(4000/4000+1000)=(4/5) 100 = 80 %

Q. If a machine performs $4000 J$ of output work and $1000 J$ is energy loss due to friction then, find efficiency of machine

20%

25%

80%

60%

Efficiency = $\frac{o u tp u t w or k}{h e a t t ak e n}$
$= \frac{4000}{4000 + 1000} = \frac{4}{5} 100 = 80%$

Q. If a machine performs 4000J of output work and 1000J is energy loss due to friction then, find efficiency of machine

20%

25%

80%

60%

Efficiency = heattakenoutputwork​ =4000+10004000​=54​100=80%

Q. If a machine performs $4000 J$ of output work and $1000 J$ is energy loss due to friction then, find efficiency of machine

Efficiency = $\frac{o u tp u t w or k}{h e a t t ak e n}$
$= \frac{4000}{4000 + 1000} = \frac{4}{5} 100 = 80%$