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Question
Mathematics
If A = [log x&-1 -log x&2] and if det (A) = 2, then the value of x is equal to
Q. If
A
=
[
l
o
g
x
−
l
o
g
x
−
1
2
]
and if
d
e
t
(
A
)
=
2
, then the value of
x
is equal to
2083
206
KEAM
KEAM 2012
Determinants
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A
2
11%
B
e
2
63%
C
-2
5%
D
e
11%
E
l
o
g
2
11%
Solution:
Given,
A
=
[
lo
g
x
−
lo
g
x
−
1
2
]
∴
∣
A
∣
=
[
lo
g
x
−
lo
g
x
−
1
2
]
=
2
lo
g
x
−
lo
g
x
=
lo
g
x
But it is given,
det
(
A
)
=
∣
A
∣
=
2
∴
2
=
lo
g
x
⇒
x
=
e
2