If a graph is plotted between log (a-x) and t, the slope of the straight line is equal to -0.03. The specific reaction rate will be

Question

If a graph is plotted between log (a-x) and t, the slope of the straight line is equal to -0.03. The specific reaction rate will be (A) 6.9 × 10-2 (B) 6.9 (C) 0.69 (D) 6.9 × 10-4

Tardigrade Admin · Accepted Answer

Graph of log (a-x) vs t is a straight line, which shows first order reaction <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/9b137fefd88c863c341960d0f67bc9ce-.png" /> k=(-2.303) ×(-0.03) =0.069=6.9 × 10-2

Q. If a graph is plotted between $lo g (a - x)$ and $t$ , the slope of the straight line is equal to $- 0.03$ . The specific reaction rate will be

$6.9 \times 1 0^{- 2}$

$6.9$

$0.69$

$6.9 \times 1 0^{- 4}$

Graph of $lo g (a - x)$ vs $t$ is a straight line, which shows first order reaction

$k = (- 2.303) \times (- 0.03)$
$= 0.069 = 6.9 \times 1 0^{- 2}$

Q. If a graph is plotted between log(a−x) and t, the slope of the straight line is equal to −0.03. The specific reaction rate will be

6.9×10−2

6.9

0.69

6.9×10−4